Question

x(y-z)+y(z-x)+z(x-y)

Answer 1

x(y-z)+y(z-x)+z(x-y)
xy-xz+yz-yx+zx-zy

now positive and negative Variable will be cancelled out

Then the answer is 0


0

Answer 2

Given:

We have given an equation which is x(y-z)+y(z-x)+z(x-y).

To Find:

We have to simplify the equation?

Step-by-step explanation:

• We have given an equation which is written as x(y-z)+y(z-x)+z(x-y).
• We will simplify the equation by the rules of BODMAS which says that firstly we solve the brackets in the given equation
• we will multiply the terms for solving the above brackets

        $xy-xz+yz-yx+zx-zy$

• Now take the like terms which are with the same variable together and simplify them solve them

        $xy-yx-xz+zx+yz-zy$

• Now we can write the xy as the yx or vice versa both are equal in maths algebra.

       $xy-xy-xz+xz+zy-zy$

• Now add ing the above equation like terms will igve us.

        $0$

• Since all the like terms cancel each other hence, we get 0

Thus, 0 is the simplified form of the equation.