Question

(x+y+-z) + (y+z-x) + (z+x-y)​

Answer 1

Answer:

x+y-z+y+z-x+z+x-y=x+y+z

Answer 2

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• (x+y+-z) + (y+z-x) + (z+x-y)
• [x+y+(-z)]+[y+z-x]+[z+x-y]
• x+y-z+y+z-x+z+x-y
• x+x-x+y+y-y+z+z-z
• $\sf{x+\cancel{x}-\cancel{x}+y+\cancel{y}-\cancel{y}+z+\cancel{z}-\cancel{z}   }$ 
• x+y+z

Hence,

(x+y+-z) + (y+z-x) + (z+x-y)=x+y+z