Question

x(y-z)-y(z-x)-z(x-y) ​

Answer 1

Answer:

2xy - 2xz

Step-by-step explanation:

x(y-z)-y (z-x) - z(x - y) =

It's easy to solve this if you solve it as though they are numbers:

Firstly, solve the brackets.

Remember:

Negative Multiplied by Negative is Positive;

Positive Multiplied by Negative is Negative:

Positive Multiplied by Positive is Positive.

So,

x(y-z)-y (z-x) - z(x- y) = xy - xz - yz + xyzx + zy

To make it clearer :

(xxy) + (xx-z) + (-yxz) + (-yx -x)+(-zxx) + (-zx-y)

= (xy) + (-xz) + (- yz ) + ( + xy ) + ( zx) + ( + zy)

= xy-xz-yz + xy - zx + zy

Now group it together.

Note: - z and - za is the same.

(x×y) + ( x × −z ) + ( −y × z ) + (−y x -x)+(-zxx) + (-zx-y)

= ( xy ) + (-xz ) + (- yz ) + ( + xy ) + ( zx) + ( + zy)

= xy - xz - yz + xy - zx + zy

= xy + xy - xz - xz - yz + yz

Now solve it.

(xxy) + (xx-z) + (-yxz) + (-yx

= (xy) + (-xz) + (-yz) + ( + xy) + ( zx) + (+zy)

= xy - xz - - yz + zx + zy xy - z

= xy + xy - xz -xz-yz yz

= 2xy - 2xz

2xy-2xz is your answer.

Answer 2

Answer:

2xy-2zx

Step-by-step explanation:

step one: remove the bracket

x(y-z)-y(z-x)-z(x-y)

xy-xz-yz+yx-zx+zy

step two: collect like terms

2xy-2xz