x^y^z.y^z^x.z^x^y =5 xyz find x+y+z
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here is one 5 in RHS so there should be one 5 also in LHS
let's say X = 5
than in RHS now became 5*5 = 25
thus in power of X there should be a two also thus y = 2
now we see that we got 50 in RHS
and in LHS on putting z = 1 we got 50
thus X = 5
y = 2 z = 1
X+y+z = 5+2+1 = 8
let's say X = 5
than in RHS now became 5*5 = 25
thus in power of X there should be a two also thus y = 2
now we see that we got 50 in RHS
and in LHS on putting z = 1 we got 50
thus X = 5
y = 2 z = 1
X+y+z = 5+2+1 = 8
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