Question

x×y°×z^-1 =? answer


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Answer 1

Answer:

It is given that xyz=1

Therefore xy=z−1

Now the equation:

LHS:

(1+x+y−1)−1+(1+y+z−1)−1+(1+z+x−1)−1

=(1+x+1y)−1+(1+y+xy)−1+(1+1xy+1x)−1

=(y+xy+1y)−1+(y+xy+11)−1+(y+xy+1xy)−1

=(y1+xy+y)+(11+xy+y)+(xy1+xy+y)

=y+xy+1y+xy+1

=1

RHS:

1

Therefore LHS=RHS

Hence Prooved !!!