Question

x×y°×z^-1 =? answer ​

Answer 1

Answer:

Step-by-step explanation:

The value of  is proven.

Solution:

Given:

xyz = 1

To prove:  =1

From xyz = 1, we can take    

Normally, the power -1 is considered as the denominator.

Hence proved that the value o

Answer 2

It is given that xyz=1xyz=1

Therefore xy=z−1xy=z−1

Now the equation:

LHS:LHS:

(1+x+y−1)−1+(1+y+z−1)−1+(1+z+x−1)−1(1+x+y−1)−1+(1+y+z−1)−1+(1+z+x−1)−1

=(1+x+1y)−1+(1+y+xy)

=(y+xy+1y)−1+(y+xy+11)−1+(y+xy+1xy)−1=(y+xy+1y)−1+(y+xy+11)−1+(y+xy+1xy)−1

=(y1+xy+y)+(11+xy+y)+(xy1+xy+y)=(y1+xy+y)+(11+xy+y)+(xy1+xy+y)

=y+xy+1y+xy+1=y+xy+1y+xy+1

=1=1

RHS:RHS:

11

Therefore LHS=RHSLHS=RHS