Question

+ x[y2+z²)+y(z2 + x²)+z(x² + y²)+2xyz​

Answer 1

Answer:

Step by Step Solution:

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Reformatting the input :

Changes made to your input should not affect the solution:

(1): "y2" was replaced by "y^2". 6 more similar replacement(s).

STEP

1

:

Trying to factor as a Difference of Squares

1.1 Factoring: x2-y2

Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

Proof : (A+B) • (A-B) =

A2 - AB + BA - B2 =

A2 - AB + AB - B2 =

A2 - B2

Note : AB = BA is the commutative property of multiplication.

Note : - AB + AB equals zero and is therefore eliminated from the expression.

Check : x2 is the square of x1

Check : y2 is the square of y1

Factorization is : (x + y) • (x - y)

Equation at the end of step

1

:

(((x•((y2)+(z2)))+(y•((z2)+(x2))))+z2•(x+y)•(x-y))+2xyz

STEP

2

:

Equation at the end of step 2

(((x•((y2)+(z2)))+y•(x2+z2))+z2•(x+y)•(x-y))+2xyz

STEP

3

:

Equation at the end of step 3

((x•(y2+z2)+y•(x2+z2))+z2•(x+y)•(x-y))+2xyz

STEP

4

:

Final result :

x2y + x2z2 + xy2 + 2xyz + xz2