(x+yi)+(3-2i)=1+4i find x and y
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Answer:
x = -2, y = 6
Step-by-step explanation:
Given:
(x+iy)+(3-2i) = 1+4i
(x+3) + i(y-2) = 1 + 4i
Equating real and imaginary value on both the sides
Real value:
x + 3 = 1
x = -2
Imaginary value:
y - 2 = 4
y = 6
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