x+z=1,y+z=1,x+y=4 solve by using cramers rule
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Answered by
3
x=2, y=2 , z=-1
x+z=1--------1
y+z=1---------2
x+y=4--------3
then,
subtract the equation =3-2
(x+y)-(y+z)=4-1
x+y-y-z=3
x-z=3-----------4
now, by adding the equation 1+4
we get,
(x+z)+(x-z) =3+1
x+z+x-z =4
2x=4
x=4/2
x=2*****
by putting the value of x in equation 1, we get,
x+z=1
2+z=1
z=1-2
z=-1 *****
by putting the value of z in equation 2, we get,
y+z=1
y+(-1)=1
y-1=1
y=1+1
y=2 *******
hence, x=2
y=2
z=-1
Answered by
4
Answer:
x=2
y=2
z=1
hope it is useful
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