Question

=
{
x
∈
Z
:
e
x
3
−
4
x
2
−
7
x
+
10
=
1
}
and
B
=
{
x
∈
Z
:
(
1
−
x
2
)
(
x
2
−
2
x
−
8
)
≥
0
}
,
then
n
[
(
A
∪
B
)
×
(
A
∩
B
)
]
is

Answer 1

Step-by-step explanation:

what is this stuff.....