Question

X1= 3√2 ; d = √2
xd = X1 + d = ?
X3 = X2 + d = ?
X4 = X3 + d = ?
Answer please​​

Answer 1

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★Given

• X1= 3√2 ______eq(0)
• d = √2 _______eq(1)

★To find

• x2 = X1 + d = ? _______eq(2)
• X3 = X2 + d = ? _______eq(3)
• X4 = X3 + d = ? ________eq(4)

★Solution

★Substituting the value of "d" and "X1" from eq (0)and (1) in eq(2), (3) ,(4).

We get

$= > x2 = 3 \sqrt{2 } + \sqrt{2} = 4\sqrt{2}$

$= > x3 = 4 \sqrt{2} + \sqrt{2} = 5 \sqrt{2}$

$= > x4 = 5 \sqrt{2} + \sqrt{2} = 6 \sqrt{2}$

★Note : In the above question u just have to put the value of "d" and the "X1" in the next equation i.e. "X2" and then again put the value "d" and "x2" in the next one and just repeat it .

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Answer 2

Answer:

Given

• X1= 3√2 ______eq(0)
• d = √2 _______eq(1)

To find

• x2 = X1 + d = ? _______eq(2)
• X3 = X2 + d = ? _______eq(3)
• X4 = X3 + d = ? ________eq(4)

Solution

Substituting the value of "d" and "X1" from eq (0)and (1) in eq(2), (3) ,(4).

We get

$= > x2 = 3 \sqrt{2 } + \sqrt{2} = 4\sqrt{2}$

$= > x3 = 4 \sqrt{2} + \sqrt{2} = 5 \sqrt{2}$

$= > x4 = 5 \sqrt{2} + \sqrt{2} = 6 \sqrt{2}$

*Note : In the above question u just have to put the value of "d" and the "X1" in the next equation i.e. "X2" and then again put the value "d" and "x2" in the next one and just repeat it .

Thanks