x1 -3b = x+b =
with formula pls
Answers
Answered by
2
Answer:
The discriminant of the quadratic equation 2x
2
+6x+b=0 is given by D=36−8b>0.
Therefore, the given equation has real roots.
we have,
x
2
x
1
+
x
1
x
2
=
x
1
⋅x
2
x
1
2
+x
2
2
=
x
1
⋅x
2
(x
1
+x
2
)
2
−2x
1
x
2
=
(b/2)
(−3)
2
−2(b/2)
=
b
18
−2<−2 [∵b<0]
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