Question

x¹/a = y¹/b= z¹/c and a+b+c=0 prove that xy=1​

Answer 1

Answer:

x^1/a=y^1/b=z^1/c=k (let)

x=k^a

y=k^b

z=k^c

xyz=k^ak^bk^c=k^(a+b+c)

or,1=k^(a+b+c)

or, k^0=k^(a+b+c);k≠0

or, a+b+c=0

Hence prove.

Step-by-step explanation: