X1,X+1,X+2 are sides of a right triangle find X and all sides
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let a = x ,b = x +1 ,c = x +2
In right angled triangle
hypotenuse = x +2
base = x+1
perpendicular = x
by Pythagoras theorem
h² = b² + p²
(x +2)² = (x +1)²+ x²
x²+4+4x = x²+1+2x + x²
x²-2x²+4x -2x +4 -1= 0
-x²+2x +3 = 0
x²-2x -3= 0
x²-3x +1x -3= 0
x (x -3) + 1(x-3)=0
(x+1)(x-3)=0
(x+1)=0 or (x-3)=0
x =-1 or x = 3
side of triangle cannot be negative. so, the value of x =3.
sides of triangle are..
a = x = 3
b = x+1 = 3+1 = 4
c = x +2 = 3+2=5
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