Question

x¹+x²+2x³= 12 3x¹+5x²+8x³= 50 x¹,x²,x³≤ 0 find the basic feasible solution

Answer 1

Answer:

here is your answer

Step-by-step explanation:

Given equation

(x2 - 5x)2 - 7(x2 - 5x) + 6 = 0

Put x2 - 5x = y

∴ The given equation becomes

y2 - 7y + 6 = 0

⇒ y2 - 6y - y + 6 = 0

⇒ y(y - 6) -1(y - 6) = 0

⇒ y = 1, 6

But x2 - 5x = y

∴ x2 - 5x = 1

x2 - 5x - 1 = 0

Here a = 1, b = -5, c = -1

∴ x =

-b±b2-4ac2a

x =

-(-5)±25+42

x =

5±292

x2 - 5x = 6

⇒ x2 - 5x - 6 = 0

⇒ x2 - 6x + x - 6 = 0

⇒ x(x - 6) +1(x - 6) = 0

⇒ (x - 6) (x + 1) = 0

⇒ x = 6 or x = -1

Hence, the roots are -1, 6,

5±292.