X1 x2 ,x2 are choosen independently find probability such that airthmetic mean of three number is equal to gemetric mean
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Let X1,X2X1,X2and X3X3 be chosen independently from the set {0,1,2,3,4}{0,1,2,3,4} each value being equally likely . What is the probability that the arithmetic mean of X1,X2X1,X2 and X3X3 is the same as their geometric mean .
My work :
My idea is to try AM≥GMAM≥GM inequality . By AM−GMAM−GM we get that equality holds only when X1=X2=X3X1=X2=X3 . So There are only 55 tuples such that X1=X2=X3X1=X2=X3 .
So required probability :
553=125
Hope it helps you.....
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