Question

X100 +2x99 +k is divisible by (x+1) value of k is

Answer 1

Step-by-step explanation:

if it's divisible by x+1, then that means that -1 is a root, so you should be able to plug in x=-1 and get 0.

if it's divisible by x+1, then that means that -1 is a root, so you should be able to plug in x=-1 and get 0. so let's do it:

if it's divisible by x+1, then that means that -1 is a root, so you should be able to plug in x=-1 and get 0. so let's do it: (-1)^100 + 2(-1)^99 + k

if it's divisible by x+1, then that means that -1 is a root, so you should be able to plug in x=-1 and get 0. so let's do it: (-1)^100 + 2(-1)^99 + k = 1 - 2 + k,

if it's divisible by x+1, then that means that -1 is a root, so you should be able to plug in x=-1 and get 0. so let's do it: (-1)^100 + 2(-1)^99 + k = 1 - 2 + k, which should equal 0, so k=1.

Answer 2

Step-by-step explanation:

g(X)=X+1

=x-(-1)

f(X)=x100+2x99+k

f(-1)=(-1)100+2(-1)99+k

=-100-198+k

=-298+k

k=298