Question

x²-0.01
factorise the following expression ​

Answer 1

Answer:

$=> x^{2} -0.01 \\\\ => x^{2} -\frac{1}{100} \\\\ => x^{2} - 10^{-2} \\\\ => x^{2} -(10^{-1})^2 \\\\ \implies [a^2-b^2=(a+b)(a-b)] \\\\ => (x+10^{-1})(x-10^{-1}) \\\\ => (x+0.1)(x-0.1)$

Answer 2

Answer:

i hope you will understand

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