Question

x² - (1 + √2)x+ √2=0​

Answer 1

Step-by-step explanation:

${x }^{2} -1 + \sqrt{2} x + \sqrt{2 } = 0$

$( {x}^{2} - 1) + \sqrt{2} (x + 1) = 0$

$(x - 1)(x + 1) + \sqrt{2} (x + 1) = 0$

$( {x}^{2} - 1) + \sqrt{2} (x + 1) = 0$

$(x + 1)(x - 1 + \sqrt{2} ) = 0$

x=-1 and x=1-sqrt{2}