Question

X2+1 has no real zeroes why

Answer 1

Given equation

$x^{2} +1=0$

Solving, we get,

$x^{2} +1=0\\\implies x^{2} =-1$

The square of any number cannot be a negative number.

Hence, the given equation has no real zeroes.

NOTE

There are roots for negative numbers under the root sign.

They are known as complex numbers.

$\sqrt{-1} = \sqrt{1} \ i\\ = i$

                                                       

Answer 2

${x}^{2} + 1 = 0 \\ \\ = > {x}^{2} = - 1 \\ \\ x = + - \iota$