Question

(x²+1)sin(3x+1) differentiate it?

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Answer 1

Explanation:

By Product Rule: (uv)′ = u′v + uv′ Here u = (x2 + 3x + 1) and v = sin x [(x2 + 3x + 1) sin x]’ = (2x + 3) × sinx + (x2 + 3x + 1) × cosx = (2x + 3)sin x + (x2 + 3x + 1)cos x

I hope answer is right