Question

x² -(1+V2)x+ V2 = 0
please solve this equation by quadratic formula please fast​

Answer 1

Answer:

{2,v²}

Step-by-step explanation:

By using shridhacharya formula,

By using shridhacharya formula, x= (1+v²)±√(1+v⁴+2v²-4v²)

By using shridhacharya formula, x= (1+v²)±√(1+v⁴+2v²-4v²)or x = 1+v²±(1-v²),

By using shridhacharya formula, x= (1+v²)±√(1+v⁴+2v²-4v²)or x = 1+v²±(1-v²),If we consider +ve sign then we have,

By using shridhacharya formula, x= (1+v²)±√(1+v⁴+2v²-4v²)or x = 1+v²±(1-v²),If we consider +ve sign then we have,x = 2

By using shridhacharya formula, x= (1+v²)±√(1+v⁴+2v²-4v²)or x = 1+v²±(1-v²),If we consider +ve sign then we have,x = 2If we consider -ve sign then we have,

By using shridhacharya formula, x= (1+v²)±√(1+v⁴+2v²-4v²)or x = 1+v²±(1-v²),If we consider +ve sign then we have,x = 2If we consider -ve sign then we have,x = 2v²

By using shridhacharya formula, x= (1+v²)±√(1+v⁴+2v²-4v²)or x = 1+v²±(1-v²),If we consider +ve sign then we have,x = 2If we consider -ve sign then we have,x = 2v²Thus x={2,v²}

I hope It was helpful to you