x²+1/(x-1)²(x+3) find the fraction
Answers
Answered by
0
Answer:
1/3-7x+x³
Step-by-step explanation:
=x²+1/(x²+1-2x)(x+3)
=x²+1/(x³+3x²+x+3-2x-6x)
=x²+1/x³+3x²+3-7x
=x²+1/3x²+3-7x+x³
=x²+1/3(x²+1)-x(7-x²)
by dividing numerator from 3(x²+1) we get
=1/3-x(7-x²)
=1/3-7x+x³ ans
Similar questions