Question

x²+1/x²+2-3x-3/x
factorise​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

The given equation is:

x^2+{\frac{1}{x^2}}-2-3x+\frac{3}{x}x

2

+

x

2

1

−2−3x+

x

3

Using the identity, (a-b)^2=a^2+b^2-2ab(a−b)

2

=a

2

+b

2

−2ab , we have

(x-\frac{1}{x})^2=x^2+{\frac{1}{x^2}-2

Thus, the given equation becomes,

x^2+{\frac{1}{x^2}}-2-3x+\frac{3}{x}=(x-\frac{1}{x})^2-3x+{\frac{3}{x}

=(x-\frac{1}{x})^2-3(x-{\frac{1}{x}})(x−

x

1

)

2

−3(x−

x

1

)

=(x-{\frac{1}{x})(x-\frac{1}{x}-3)