Question

X²+1/x²=34then find x-1/x​

Answer 1

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Answer 2

$\huge \mathfrak \red{answer}$

$\bf{ \boxed{ \underline{ \pink{ \tt{ = \frac{ + }{ - } \sqrt{6} \: }}}}}$

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$\sf \huge\underline \blue{Question}$

$\rm{ {x}^{2} + \dfrac{1}{ {x}^{2} } = 34 \: then \: find \: x + \dfrac{1}{x}}$

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$\sf \underline \orange{step \: by \: step \: explanation}$

$\tt \red{ \implies \: {x}^{2} + \dfrac{1}{ {x}^{2} } = 34}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf{now \: adding \: both \: 2 \: sides}$

$\tt \blue{ \implies \: {x}^{2} + \dfrac{1}{ {x}^{2} } + 2 = 34 + 2}$

$\tt \purple{ \implies \: {x}^{2} + \dfrac{1}{ {x}^{2} } + 2 \times x \times \dfrac{1}{x} = 36}$

$\tt \pink{ \implies \: (x + \frac{1}{x}) {}^{2} = 36}$

$\tt \green{ \implies \: x + \dfrac{1}{x} = \frac{ + }{ - } \sqrt{36}}$

$\tt \orange{ \implies \: x + \dfrac{1}{x} = \frac{ + }{ - } \sqrt{6}}$