Question

x2 +1/x2 =38 , find the value of x -1/x=

Answer 1

Here's your answer !!

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It's given that,

$= > {x}^{2} + \frac{1}{ {x}^{2} } = 38$

We have to find value of ,

$= > x - \frac{1}{x}$

We know that,

$= > {(x - \frac{1}{x}) }^{2} = {x}^{2} + \frac{1}{ {x}^{2} } - 2 \times x \times \frac{1}{x}$

$= > {(x - \frac{1}{x} )}^{2} = {x}^{2} + \frac{1}{ {x}^{2} } - 2$

$by \: putting \: value \: of \: {x}^{2} + \frac{1}{ {x}^{2} } we \: get$

$= > {(x - \frac{1}{x}) }^{2} = 38 - 2$

$= > {(x - \frac{1}{x} )}^{2} = 36$

$= > {(x - \frac{1}{x} )} = \sqrt{36}$

$= > x - \frac{1}{x} = 6$

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Hope it helps you !! :)

Answer 2

Hey yuvaa here is your Answer..