(x²+1/x²)-4(x+1/x)+6
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Answered by
3
x+1/x =t
square on both sides
(x+1/x)^2 =t^2
x^2 +1/x^2 +2 = t^2
x^2 + 1/x^2 = t^2 -2
substitute in given equation
t^2-2 -4t +6
t^2 -4t +4
t^2 -2t -2t +4=0
t(t-2) -2(t-2)=0
(t-2)(t-2)=0
t=2,2
t=2 is answer
square on both sides
(x+1/x)^2 =t^2
x^2 +1/x^2 +2 = t^2
x^2 + 1/x^2 = t^2 -2
substitute in given equation
t^2-2 -4t +6
t^2 -4t +4
t^2 -2t -2t +4=0
t(t-2) -2(t-2)=0
(t-2)(t-2)=0
t=2,2
t=2 is answer
Answered by
8
here is ur ans........
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herione
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