Question

(x2+1/x2)-4i(x+1/x)-6
find the square root
​

Answer 1

Answer:

Correct option is

A

±(x−x1 +2i) x

2 +x 21 −i4

(x− x1 )−6=x

2 + x2

1 +4ix−4i

x1−4−2 (Using i1 =−i)=x

2 + x 2

1 +4i 2

+2×x×2i−2×2x1 ×2i−2×x× x1 ----------(Using i

2

=1)

=(x) 2+(x−1 ) 2 +(2i) 2 +2×x( x−1 )+2×(x−1 )×2i+2×x×2i

=(x− x1 +2i) 2

(Using (a+b+c) 2 =a

2 +b 2 +c

2 +2ab+2bc+2ac))

Therefore, square root of x

2 +x21 −4 (x−x1)−6 is ±(x−x1 +2i).

Hence, Option (A) is correct.

Answer 2

${\huge{\boxed{\tt{\color {red}{Answer❀✿°᭄}}}}}$

..I added +2and. -2 in second step to complete the square...!!

and after that let x+1/x be y ...so that it will become simple quadratic polynomial...!!!!.

and ans will (x+1/x -2^2....

...and second question is a a whole square .hope it helped you!!!.