x²+1/x² and (x-1/x)² , when x+1/x = 8
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Answer:
Step-by-step explanation:
Given ,
x-(1/x) = 3/2 ———(1)
Now,
[x+(1/x)]^2 = [x-(1/x)]^2 + 4x * (1/x) = (3/2)^2 + 4 = 9/4 + 4 = (16+9)/4 = 25/4
x+(1/x) = √(25/4) = 5/2 ——-(2)
x^2 - (1/x)^2
= [x+(1/x)] * [x-(1/x)]
Put (1) & (2),
= 5/2 * 3/2
= 15/4 (ans)
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