Question

(x2-1)(x2+x+1)(x2-x+1) expand​

Answer 1

$(x^2-1)(x^2+x+1)(x^2-x+1) \\ \\ (x^2-1)(x^2+1+x)(x^2+1-x) \\ \\ (x^2-1)((x^2+1)+x)((x^2+1)-x) \\ \\ (x^2-1)((x^2+1)^2-x^2) \\ \\ (x^2-1)(x^4+2x^2+1-x^2) \\ \\ (x^2-1)(x^4+x^2+1) \\ \\ x^6+x^4+x^2-x^4-x^2-1 \\ \\ \bold{x^6-1} \\ \\ \\ \\ \therefore\ (x^2-1)(x^2+x+1)(x^2-x+1)=x^6-1$

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