x²+10x+25 find the zero
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Step-by-step explanation:
We are given a Quadratic equation x^2+10x+25 and we need to find the zeroes/roots
So we use the Sridhacharya formula
x=+-root of b^2-4ac/2a
On solving the equation , we get
x=+-root of 0/2a
This equation doesn't have any real roots
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