Question

x²+10x-39. Find the zeros and relation between zeros.​

Answer 1

Answer:

the ans is x=+13 or (-3)

Answer 2

Answer:

x²+10x-39

» x²+13x -3x -39

» x(x+13) -3(x+13)

» (x-3) (x+13)

» x=3 » x= -13

therefore alfa = 3 beta = -13

alfa + beta = -b/a

3+(-13) = -10/1

-10 = -10 verified

alfa × beta = c/a

3× (-13) = -39/1

-39 = -39 hence verified

hope this will help u a lot...