Question

x2 – 11x + 28=0 y2 – 18y + 81=0

Answer 1

Answer:

1. x²-11x+28 = 0

=> x²-(4+7)x+28 = 0

=> x²-4x-7x+28 = 0

=> x(x-4)-7(x-4) = 0

=> (x-4)(x-7) = 0

so, we can say, the value of x = 4 & 7

2. y²-18y+81 = 0

=> y²-(9+9)y+81 = 0

=> y²-9y-9y+81 = 0

=> y(y-9)-9(y-9) = 0

=> (y-9)² = 0

so, we can say, the value of y = 9