x2-11x+7=0 want answer for this
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Step-by-step explanation:
First of all.....
X^2-11X+7=0
we'll check the value of discriminant...
D= b^2-4ac (Where a=1
b=-11
c=7)
D=(-11)^2-4(1)(7)
D=93
Since D is non zero, we have real and distinct roots.
Now, applying quadratic formula,
X= (-b)+-√D / 2a
X= -(-11)+-√93 / 2(1)
Hence X= 11+√93 / 2 and X=11-√93 / 2
Hope this helps you....
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