x²–12=0,Solve the given quadratic equation using factorization.
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Solution :
Given quadratic equation x² - 12 = 0
=> x² - ( 2√3 )² = 0
_____________________
We know the algebraic identity :
a² - b² = ( a + b )( a - b )
______________________
=> ( x + 2√3 )( x - 2√3 ) = 0
x + 2√3 = 0 or x - 2√3 = 0
x = -2√3 or x = 2√3
Therefore ,
-2√3 , 2√3 are two roots of
given quadratic equation.
••••
Given quadratic equation x² - 12 = 0
=> x² - ( 2√3 )² = 0
_____________________
We know the algebraic identity :
a² - b² = ( a + b )( a - b )
______________________
=> ( x + 2√3 )( x - 2√3 ) = 0
x + 2√3 = 0 or x - 2√3 = 0
x = -2√3 or x = 2√3
Therefore ,
-2√3 , 2√3 are two roots of
given quadratic equation.
••••
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