x2+12x-196=o factorise the foolowing
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Answered by
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HEY DEAR....
U CAM FACTORIES THE ABOVE EQUATION. BY USING THIS FORMULA ⬇
• -b±√b²-4ac/2a.
• a=1 ; b=12 ; c= 196.
• -12±√144-4(1)(-196)/2(1).
• -12±√144+784/2
#-12+√928/2 ; # -12-√928/2.
# -6+2√58 ; # -6-2√58.
I'M SO LAZY TO TYPE THE WHOLE ANSWER. IF U HAVE ANY DOUBT, PLZ DO ASK IN THE COMMENTS. :-)
U CAM FACTORIES THE ABOVE EQUATION. BY USING THIS FORMULA ⬇
• -b±√b²-4ac/2a.
• a=1 ; b=12 ; c= 196.
• -12±√144-4(1)(-196)/2(1).
• -12±√144+784/2
#-12+√928/2 ; # -12-√928/2.
# -6+2√58 ; # -6-2√58.
I'M SO LAZY TO TYPE THE WHOLE ANSWER. IF U HAVE ANY DOUBT, PLZ DO ASK IN THE COMMENTS. :-)
Answered by
0
x² + 12 x - 196 = 0
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= x² + 12 x - 196
Using Quadratic Formula = -b+√b²-4 ac/2 a ; -b-√b²-4 ac/2 a
Then, x = -12+√(12)²-4(1)(-196) / 2(1) ; -12-√(12)²-4(1)(-196) / 2(1)
x = -12+√144+784 / 2 ; -12-√144+784 / 2
x = -12+√928 / 2 ; -12-√928 / 2
x = -12+4√58 / 2 ; -12-4√58 / 2
x = -6+2√58 ; -6-2√58
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☺ ☺ ☺ Hope this Helps ☺ ☺ ☺
_______________________________________________________
= x² + 12 x - 196
Using Quadratic Formula = -b+√b²-4 ac/2 a ; -b-√b²-4 ac/2 a
Then, x = -12+√(12)²-4(1)(-196) / 2(1) ; -12-√(12)²-4(1)(-196) / 2(1)
x = -12+√144+784 / 2 ; -12-√144+784 / 2
x = -12+√928 / 2 ; -12-√928 / 2
x = -12+4√58 / 2 ; -12-4√58 / 2
x = -6+2√58 ; -6-2√58
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☺ ☺ ☺ Hope this Helps ☺ ☺ ☺
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