Question

x2 +12x-20/3x-5=x2 +8x+12/2x+3







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Answer 1

Answer:

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Answer 2

$\boxed{\mathsf \red{ \frac{ {x}^{2} + 12x - 20 }{3x - 5} = \frac{ {x}^{2} + 8x + 12 }{2x + 3} }} \\ \\ \mathsf{(2x + 3).( {x}^{2} + 12x - 20) \: = \: (3x - 5).( {x}^{2} + 8x + 12)} \\ \\ \mathsf{2 {x}^{3} + 27 {x}^{2} - 4x - 60 = 3 {x}^{3} + 19 {x}^{2} - 4x - 60 } \\ \\ \mathsf{27 {x}^{2} - 19 {x}^{2} = 3 {x}^{3} - 2 {x}^{3} } \\ \\ \mathsf{8 {x}^{2} = {x}^{3} } \\ \\ \boxed{ \mathsf{x = 8}}$

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