Question

x²-12x+36=0 solve using factorisation​

Answer 1

ANSWER

$x^{2} -12x+36=0$

$x^{2} -6x-6x+12=0$

$x(x-6)+6(x-6)=0$

$(x-6)(x+6)=0</p><p>\\(x-6)=0 or (x+6)=0\\</p><p>x=6 or x=-6$