Question

x²+13x+40 solve in.middle term​

Answer 1

Answer:

x^2+8x+5x+40

X(X+8)+5(X+8)

(X+5) (X+8)

hence, X=-5 or -8

Answer 2

${\large{\pmb{\sf{\underline{RequirEd \; Solution...}}}}}$

⋆ Given expression is ${\pmb{\sf{\red{x^{2}+13x+40}}}}$ We have to solve this expression by using middle term splitting method. Let us solve this question!

${\bigstar \:{\pmb{\sf{\purple{\underline{\underline{Middle \: term \: splitting \: method...}}}}}}}$

${\sf{:\implies x^{2}+13x+40}}$

${\sf{:\implies x^{2} + (8+5)x + 40}}$

${\sf{:\implies x^{2} + 8x + 5x + 40}}$

${\sf{:\implies x(x) + (2 \times 2 \times 2) + 5(x) + (2 \times 2 \times 2)}}$

${\sf{:\implies x(x) + (4 \times 2) + 5(x) + (4 \times 2)}}$

${\sf{:\implies x(x) + (8) + 5(x) + (8)}}$

${\sf{:\implies x(x+8) + 5(x+8)}}$

${\sf{:\implies (x+8) (x+5) = 0}}$

${\sf{:\implies x \: = 0-8 \: or \: x =\: 0-5}}$

${\sf{:\implies x = \: -8 \: or \: x \: = -5}}$

${\pmb{\tt{Henceforth, \: x \: = -8 \: or \: -5}}}$

${\pmb{\tt{Henceforth, \: solved!}}}$

${\large{\pmb{\sf{\underline{Additional \; KnowlEdge...}}}}}$

Some knowledge about Quadratic Equations -

★ Sum of zeros of any quadratic equation is given by ➝ α+β = -b/a

★ Product of zeros of any quadratic equation is given by ➝ αβ = c/a

★ Discriminant is given by b²-4ac

• Discriminant tell us about there are solution of a quadratic equation as no solution, one solution and two solutions.

★ A quadratic equation have 2 roots

★ ax² + bx + c = 0 is the general form of quadratic equation

★ D > 0 then roots are real and distinct.

★ D = 0 then roots are real and equal.

★ D < 0 then roots are imaginary.

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