Question

x²-13x+42=0
Solve by Quadratic Equations​

Answer 1

Solving by quadratic formula..

x= - b +- ✓b^2-4ac/2a

a=1,b=-13,c=42

x=(1)+-✓(-13)^2-4×1×42/2×1

x=1+-✓169-168/2

x=1+-✓1/2 ( squaring a root )

x=1+-✓(1)^2/2 ( square root cut by its square )

x=1+-(1)/2

x=1+1/2=2/2=1..

x=1-1/2=0/2=0..

VALUE OF X=1,0..

Answer 2

Answer:

$x = 1,0$

Step-by-step explanation:

It is the correct answer.