Math, asked by sheejajamaludheen, 11 hours ago

x²+(14-x) ²=14² find the value of x​

Answers

Answered by dkchakrabarty01
1

Answer:

x^2+(14-x)^2-14^2=0

x^2+14^2-28x+x^2-14^2=0

2x2-28x=0

x^2-14x=0

x(x-14)=0

x=0 and x=14

Answered by nareshjangra501
1

Step-by-step explanation:

x*2+(14-x)*2=14*2

x*2+14*2-x*2=196

x*2-x*2+14*2=196

x+14*2=196

x+196=196

x=196-196

x=0

I think it will be Answer ☺️☺️

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