Question

x²-14x+48=0 solve the following quadratic equation by factorization method​

Answer 1

Answer:

x^2-14x+48=0

=x^2-(8+6)x+48 =0

=x^2-8x-6x+48=0

=x(x-8) -6(x-8)=0

=(x-8)(x-6)=0

is, or,

x-8=0 x-6=0

=x=8 =x=6

ans x=8,6

Answer 2

${x}^{2} + 14x + 48 \\ on \: splitting - \\ = {x}^{2} + 8x + 6x + 59 \\ = x(x + 8) + 6(x + 8) \\ we \: get \\ (x + 6)(x + 8) \:$