Question

x² - 14x + 48=0

y²- 9y +20=0​

Answer 1

Answer:

x^2- 14x +48 =0

(x-6) (x-8)=0

×=6 or x=8

Now,

y^2-9y+20=0

(y-4)( y-5) =0

y= 4 or y=5

Answer 2

Answer:

x² - 14x + 48=0

x² - 6x - 8x + 48=0

x( x- 6) - 8(x - 6) =0

(x-8)(x-6) = 0

x= 8 OR x = 6

y²- 9y +20=0​

y²- 4y -5y +20=0​

y(y-4)-5(y-4) = 0

(y-4)(y-5) = 0

y = 4 OR y=5