Question

x² +15-___=8x-___place polynomial on one side and set equation to zero by additive inverse property

Answer 1

Answer:

first u solve the equation with variable one side and consonant another side placing = in between both and take out your answers. applying this formula

Step-by-step explanation:

x

Answer 2

$3,5$are the value for x from place polynomial on one side and set equation to zero by additive inverse property.

Given:

From the question,$\[{{x}^{2}}\text{+ 15 }=8x~\]$  is the equation.

To find:

The value of  polynomial on one side and set equation to zero by additive inverse property

Step-by-step explanation:

where $8x$  is used to subtract on both sides to make a polynomial on one side and set the equation to zero by additive inverse property.

$\[ & {{x}^{2}}+15-8x=8x-8x \\ \\ & {{x}^{2}}+15-8x=0 \\ \end{align}\]$

Factoring Polynomial equation ${{x}^{2}}+15-8x=0$

we get,

$\[ & (x-5)(x-3)=0 \\ \\ & x-5+5=0+5 \\ \\ & x=5 \\ \\ & x-3+3=0+3 \\ \\ & x=3 \\ \\ & x=5,x=3 \\ \\\end{align}\]$are solved by using the additive inverse property.

Hence the value for x is  $3,5$ .