Question

x²-15 x +54 solve the following quadratic equation by factoruzation .​

Answer 1

$\huge\fbox\pink{✯Answer✯}$

• $x²-15 x +54 =0$

• ${x²-9x-6x+54 =0}$

• ${x( x -9 )-6(x- 9) =0}$

• $(x-9) (x-6)=0$

• $X - 9=0, x-6=0$

• $x=9 ,x=6$

$\small\fbox\green{✯x = 9 x = 6✯}$

$\huge\boxed{\dag\sf\red{Therefore}\dag}$

• 9 and 6 are roots of given quadratic equation.

• mark it as brainlist !

Answer 2

Answer:

x²−15x+54=0

{x²-9x-6x+54 =0}x²−9x−6x+54=0

{x( x -9 )-6(x- 9) =0}x(x−9)−6(x−9)=0

(x-9) (x-6)=0(x−9)(x−6)=0

X - 9=0, x-6=0X−9=0,x−6=0

x=9 ,x=6x=9,x=6

Therefore†

9 and 6 are roots of given quadratic equation.

mark it as brainlist !