Question

X2-15x+54=0. quadratic equation by factorization method​

Answer 1

$\huge{x = \frac{ - b \underline + \sqrt{ {b}^{2} - 4ac} }{2a} }$

$\huge{ {x}^{2} -15x+54=0}$

a=1

b=-15

c=54

$\large{x = \frac{ - ( - 15) \underline + \sqrt{ {( - 15)}^{2} - 4 \times 1 \times 54} }{2 \times 1} }$

$\huge{x = \frac{15 \underline + 3}{2} }$

$\huge{x = \frac{15 + 3}{2} }$

$\huge{x = \frac{15 - 3}{2} }$

$\huge{x = 9}$

$\huge{x = 6}$

Answer 2

Answer:

X² – 15x + 54 = 0

⇒ x² - 9x - 6x + 54 = 0

⇒ x (x - 9) - 6 (x - 9) = 0

⇒ (x - 6) (x - 9) = 0

⇒ (x - 6) = 0 or (x - 9) = 0

⇒ x = 6 or x = 9

So, 6 and 9 are the roots of the given quadratic equation.