Question

x²-15x+54=0 quadratic equation factorisation
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Answer 1

hope this helps u

x²-15x+54

x²-6x-9x+54

(x²-6x) ( -9x+54)

x(x-6)      -9(x-6)

 the factors of x²-15x+54 = (x-6) (x-9)

Answer 2

Question :-

x²-15x+54=0

What to find out = Roots of the equation?

Solution :-

Factorise by splitting middle term

${x}^{2} - 15x + 54 = 0 \\ \\ {x}^{2} - 9x - 6x + 54 = 0 \\ \\ x(x - 9) - 6(x - 9) = 0 \\ \\ (x - 9)(x - 6) = 0$

Now split it into possible cases

$(x - 9) = 0 \\ \\ (x - 6) = 0$

Hence,

$x_1 = 9 \\ \\ x_2 = 6$

Extra information :-

• A quadratic equation is an equation of the second degree, meaning it contains at least one term that is squared. The standard form is ax² + bx + c = 0 with a, b, and c being constants, or numerical coefficients, and x is an unknown variable.