x²–15x+56=0,Solve the given quadratic equation using factorization.
Answers
Answered by
1
hey here is ur answer
x^2 - 15x+56=0
x^2-8x-7x+56=0
x(x-8)-7(x-8)=0
(x-7)(x+8)=0
I hope this helps u
x^2 - 15x+56=0
x^2-8x-7x+56=0
x(x-8)-7(x-8)=0
(x-7)(x+8)=0
I hope this helps u
Answered by
3
hey user!!!
given :- x² - 15x + 56 = 0
>> x² - ( 7x + 8x ) + 56 = 0
>> x² - 7x - 8x + 56 = 0
>> x ( x - 7 ) - 8 ( x - 7 ) = 0
>> ( x - 7 ) ( x - 8 ) = 0
>> x - 7 = 0
= 7
OR
>> x - 8 = 0
= 8
x = 7 or 8
cheers!!!
given :- x² - 15x + 56 = 0
>> x² - ( 7x + 8x ) + 56 = 0
>> x² - 7x - 8x + 56 = 0
>> x ( x - 7 ) - 8 ( x - 7 ) = 0
>> ( x - 7 ) ( x - 8 ) = 0
>> x - 7 = 0
= 7
OR
>> x - 8 = 0
= 8
x = 7 or 8
cheers!!!
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