Math, asked by aman1081, 1 year ago

x²+162x+6561
 {x }^{2}  + 162x + 6561

Answers

Answered by Anonymous
2
Hey there !!
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x² + 162x + 6561 = 0

x² + 81x + 81 x + 6561 = 0

x ( x + 81 ) + 81 ( x + 81 ) = 0

( x + 81 ) ( x + 81 ) = 0

( x + 81 ) = 0

x = – 81
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