Question

x²-17x+16 solve in middle term​

Answer 1

Answer:

x^2-16x-x+16

X(x-16)-1(x-16)

(x-1) (x-16)

hence, X=1 or 16

Answer 2

${\large{\pmb{\sf{\underline{RequirEd \; Solution...}}}}}$

⋆ Given expression is ${\pmb{\sf{\red{x^{2}-17x+16}}}}$ We have to solve this expression by using middle term splitting method. Let us solve this question!

${\bigstar \:{\pmb{\sf{\purple{\underline{\underline{Middle \: term \: splitting \: method...}}}}}}}$

${\sf{:\implies x^{2}-17x+16}}$

${\sf{:\implies x^{2}-16x-x+16}}$

${\sf{:\implies x^{2}-x-16x+16}}$

${\sf{:\implies x(x) - (1) - 2 \times 2 \times 2 \times 2(x)-(1)}}$

${\sf{:\implies x(x) - (1) - 4 \times 2 \times 2(x)-(1)}}$

${\sf{:\implies x(x) - (1) - 4 \times 4(x)-(1)}}$

${\sf{:\implies x(x) - (1) - 16(x) - (1)}}$

${\sf{:\implies x(x-1) - 16(x-1)}}$

${\sf{:\implies (x-1) (x-16) = 0}}$

${\sf{:\implies x = 0+1 \: or\: x = 0+16}}$

${\sf{:\implies x = 1 \: or\: x = 16}}$

${\pmb{\tt{Henceforth, \: x \: = 1 \: or \: 16}}}$

${\pmb{\tt{Henceforth, \: solved!}}}$

${\large{\pmb{\sf{\underline{Additional \; KnowlEdge...}}}}}$

Some knowledge about Quadratic Equations -

★ Sum of zeros of any quadratic equation is given by ➝ α+β = -b/a

★ Product of zeros of any quadratic equation is given by ➝ αβ = c/a

★ Discriminant is given by b²-4ac

• Discriminant tell us about there are solution of a quadratic equation as no solution, one solution and two solutions.

★ A quadratic equation have 2 roots

★ ax² + bx + c = 0 is the general form of quadratic equation

★ D > 0 then roots are real and distinct.

★ D = 0 then roots are real and equal.

★ D < 0 then roots are imaginary.

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